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Sagot :
We will solve as follows:
[tex]4(x-5)+10>2(5x-2)-4\Rightarrow4x-20+10>10x-4-4x[/tex][tex]\Rightarrow4x-10>6x-4\Rightarrow-2x>6\Rightarrow x<-3[/tex]So, the solution is x < -3.
***Breakdown:
*After we obtain:
[tex]4x-10>6x-4[/tex]We operate like terms, that is we separate the variables and integers in the different side [Operating as if it were a normal equation]:
[tex]\Rightarrow4x-6x>-4+10\Rightarrow-2x>6[/tex]After this, we know that by dividing and/or multiplying by negative values in the inequality the orientation of the inequality will shift [That is if it was "<" then it will become ">" and viceversa], that is:
[tex]\Rightarrow x<\frac{6}{-2}\Rightarrow x<-3[/tex]
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