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Sagot :
We want to solve
2x^2–9=11
First, isolate the portion of the equation that's actually being squared. That is:
2x^2 = 11 + 9
that is equivalent to:
2x^2 = 20
that is equivalent to
x^2 = 20/ 2 = 10
that is
x^2 = 10
Now square root both sides and simplify, that is:
[tex]\sqrt[]{x^2\text{ }}=\text{ }\sqrt[]{10}[/tex]we know that the square root is the inverse function of the function x^ 2, so we can cancel the square :
[tex]x\text{ = }\sqrt[]{10}[/tex]but note that there is always the possibility of two roots for every square root: one positive and one negative: so the final answer is:
[tex]x\text{ = +/- }\sqrt[]{10}[/tex]
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