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what is the 13 term of the sequence 2,6,18,54

Sagot :

Notice that:

[tex]\begin{gathered} 2=2\times3^0, \\ 6=2\times3^1, \\ 18=2\times3^2, \\ 54=2\times3^3. \end{gathered}[/tex]

Therefore, the rule to compute the nth term of the sequence is:

[tex]a_n=2\times3^{n-1}.[/tex]

Substituting n=13 in the above equation we get:

[tex]a_{13}=2\times3^{13-1}=2\times3^{12}=1062882.[/tex]

Answer: 1062882.

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