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Consider the following function. Complete parts (a) through (e) below.f(x)=x²-2x-8The vertex is.(Type an ordered pair.)c. Find the x-intercepts. The x-intercept(s) is/are(Type an integer or a fraction. Use a comma to separate answers as needed.)d. Find the y-intercept. The y-intercept is(Type an integer or a fraction.)e. Use the results from parts (a)-(d) to araph the quadratic function.

Sagot :

Given the function:

[tex]f(x)=x^2-2x-8[/tex]

It is a quadratic function where:

a=1

b= -2

c= -8

The x-coordinate of the vertex is given by:

[tex]x=-\frac{b}{2a}[/tex]

Substitute a and b:

[tex]x=-\frac{-2}{2(1)}=\frac{2}{2}=1[/tex]

Substituting in the original equation to obtain the y-coordinate, we obtain:

[tex]y=(1)^2-2(1)-8=1-2-8=-9[/tex]

So, the vertex is (0, -9)

c. For the intercept at x we make y = 0:

[tex]0=x^2-2x-8[/tex]

And solve for x by factorization:

[tex]\begin{gathered} (x-4)(x+2)=0 \\ Separate\text{ the solutions} \\ x-4=0 \\ x-4+4=0+4 \\ x=4 \\ and \\ x+2=0 \\ x+2-2=0-2 \\ x=-2 \end{gathered}[/tex]

So, the x-intercepts are:

(-2, 0) and (4,0)

Answer: (-2,0), (4,0)

d. For the intercept at y we make x = 0:

[tex]y=(0)^2-2(0)-8=-8[/tex]

So the y-intercept is (0, -8)

Answer: (0, -8)

e. Graphing the function:

View image ElleannaD418971
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