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260grams
The formula for calculating the moles of NaOH is expressed as
[tex]\begin{gathered} moles=molarity\times volume \\ moles\text{ of NaOH}=1.0M\times6.5L \\ moles\text{ of NaOH}=6.5moles \end{gathered}[/tex]Determine the required mass of NaOH
[tex]\begin{gathered} Mass\text{ of NaOH}=moles\times molar\text{ mass} \\ Mass\text{ of NaOH}=6.5\cancel{moles}\times\frac{40g}{\cancel{mole}} \\ Mass\text{ of NaOH}=260grams \end{gathered}[/tex]Hence the grams of sodium hydroxide (NaOH) you need to make 6.5 L of 1.0M solution is 260grams