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How many grams of sodium hydroxide (NaOH) do you need to make 6.5 L of 1.0M solution?

Sagot :

Answer:

260grams

Explanations:

The formula for calculating the moles of NaOH is expressed as

[tex]\begin{gathered} moles=molarity\times volume \\ moles\text{ of NaOH}=1.0M\times6.5L \\ moles\text{ of NaOH}=6.5moles \end{gathered}[/tex]

Determine the required mass of NaOH

[tex]\begin{gathered} Mass\text{ of NaOH}=moles\times molar\text{ mass} \\ Mass\text{ of NaOH}=6.5\cancel{moles}\times\frac{40g}{\cancel{mole}} \\ Mass\text{ of NaOH}=260grams \end{gathered}[/tex]

Hence the grams of sodium hydroxide (NaOH) you need to make 6.5 L of 1.0M solution is 260grams

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