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What is the surface area of a pyramid if its one triangular face has an area of 20 sq. cm and its square base has a side of 5cm?A. 100 sq.cmB. 105 sq.cmC. 110 sq. cmD. 115 sq.cm

Sagot :

To solve this problem, we will use the following formula for the surface area of a square pyramid:

[tex]SA=BA+4A_t,[/tex]

where BA= base area, and A_t is the area of one of the lateral triangles.

Now, we are given that:

[tex]A_t=20cm^2.[/tex]

Recall that the area of a square is given by the following formula:

[tex]A_s=side^2.[/tex]

We are given that the side of the base is 5 cm long, therefore, the base area is:

[tex]A_s=(5cm)^2=25cm^2.[/tex]

Finally, we get that:

[tex]SA=25cm^2+4(20cm^2)=105cm^2.[/tex]

Answer:

[tex]105cm^2.[/tex]

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