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Frank's rectangular box of toys has a perimeter of 30 inches. The length is twice as long as the width. Which of the following expressions could be a major step in finding the length? A. Length times Width equals AreaB. 2 times Width plus 2 times Width plus Width plus Width equals 30C. Perimeter equals Width plus Width plus Width plus WidthD. 2 times Length equals Width

Sagot :

From the given problem,

length is twice as long as the width

length = 2 x width

Note that the perimeter is :

[tex]P=2W+2L[/tex]

where W and L are the width and length respectively.

Since L = 2W

Perimeter will be :

[tex]\begin{gathered} P=2W+2(2W) \\ P=2W+4W \\ P=6W \end{gathered}[/tex]

Perimeter is equal to 30 inches :

[tex]6W=30in[/tex]

From the given choices, only B satisfies this condition.

2W + 2W + W + W = 30

6W = 30

Therefore, the answer is B.

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