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f(1)= 8 1/2; f(n)= f( n-1) - 1/2; 5 1/2. Find the position of the given term

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Sagot :

Answer:

7th position

Explanation:

The first term is f(1) = 8 1/2

So, the second term is:

f(n) = f(n-1) - 1/2

f(2) = f(2-1) - 1/2

f(2) = f(1) - 1/2

f(2) = 8 1/2 - 1/2

f(2) = 8

Then, we can calculate the next terms until we get 5 1/2 as:

[tex]\begin{gathered} f(3)=f(2)-\frac{1}{2}=8-\frac{1}{2}=7\frac{1}{2} \\ f(4)=f(3)-\frac{1}{2}=7\frac{1}{2}-\frac{1}{2}=7 \\ f(5)=f(4)-\frac{1}{2}=7-\frac{1}{2}=6\frac{1}{2} \\ f(6)=f(5)-\frac{1}{2}=6\frac{1}{2}-\frac{1}{2}=6 \\ f(7)=f(6)-\frac{1}{2}=6-\frac{1}{2}=5\frac{1}{2} \end{gathered}[/tex]

So, f(7) is equal to 5 1/2. It means that the position of the term is the 7th position.