For it we need to find the volume of the cone
The formula is
[tex]V=\frac{\pi r^2h^{}}{3}[/tex]
we know the height 3 units but we dont have the radious then we use a right triangle to calculate
to find r we apply pythagoras
[tex]a^2+b^2=h^2^{}[/tex]
where a and b are sides of the triangle and h the hypotenuse
[tex]\begin{gathered} 3^2+r^2=5^2 \\ 9+r^2=25 \\ r^2=25-9 \\ r^2=16 \\ r=4 \end{gathered}[/tex]
the radious is 4 units, now replace on the formula of the volume
[tex]\begin{gathered} V=\frac{\pi\times4^2\times3}{3} \\ \\ V=\frac{\pi\times16\times3}{3} \\ \\ V=16\pi\approx50.3 \end{gathered}[/tex]
Volume of the cone is 50.3 square units, then right option is third
