Charmaine made 3 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for all 3 necklaces was $16.80. If the beads cost $2.70 for each necklace, how much did each pendant cost? sti U BO

Question

03-11-2022
Mathematics

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Charmaine made 3 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for all 3 necklaces was $16.80. If the beads cost $2.70 for each necklace, how much did each pendant cost? sti U BO

Sagot :

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Info given

Charmaine made 3 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for all 3 necklaces was $16.80. If the beads cost $2.70 for each necklace, how much did each pendant cost?

Solution

For this case let's assume that beads cost x and necklaces y we can set up the following equation:

[tex]3(x+y)=16.80[/tex]

Where x and y represent the unitary prices. And we know that x= 2.70 so then we just need to solve for y like this:

[tex]3(2.70+y)=16.80[/tex]

And solving for y we got:

[tex]y=\frac{16.80}{3}-2.70=2.90[/tex]

So then each pendant cost 2.9$ for this case

Sagot :

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