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In ΔMNO, the measure of ∠O=90°, ON = 16, NM = 65, and MO = 63. What ratio represents the cotangent of ∠M?

Sagot :

We can represent this triangle as follows:

We have six trigonometric ratios that can be applied to a right triangle like the one above.

We have that the ratio cotangent is given by:

[tex]\cot (\theta)=\frac{adj}{opp}[/tex]

That is, the ratio cotangent is the adjacent side to the angle to the opposite side of the angle. In this case, the reference angle is [tex]\cot (\theta)=\frac{MO}{ON}\Rightarrow cot(\theta)=\frac{63}{16}[/tex]

Therefore, the ratio is cot(theta) = 63/16.

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