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Sagot :
Given:
Deposit amount = $1200
Time = 12 years
Interest rate = 6.5%
Find -:
Amount after 12 years
Explanation-:
Compounded interest formula:
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]Where,
[tex]\begin{gathered} A=\text{ Final amount} \\ \\ P=\text{ Initial principal balance } \\ \\ r=\text{ Interest rate} \\ \\ n=\text{ Number of times interest applied per time period} \\ \\ t=\text{ Time} \end{gathered}[/tex]The final amount is:
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \\ A=1200(1+\frac{6.5}{100})^{12} \\ \\ A=1200(1+0.065)^{12} \\ \\ \end{gathered}[/tex]The amount after 12 years:
[tex]\begin{gathered} A=1200(1.065)^{12} \\ \\ A=1200\times2.1291 \\ \\ A=2554.92 \end{gathered}[/tex]The amount after 12 years is $2554.92
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