Here, we want to get the equation of the trend line
Since the trend line is linear, it follows that the equation of the line can be written in the form;
[tex]y\text{ = mx + b}[/tex]where m is the slope and b is the y-intercept
We can easily get the y-intercept from the graph
The y-intercept is at 110
What is left is to get the slope
To get the slope, we select a point on the trend line
The point we have selected is (30,50)
Simply substitute 30 for x and 50 for y
We have this as;
[tex]\begin{gathered} 50\text{ = 30m + 110} \\ 30m\text{ = -110+50} \\ \\ 30m\text{ = -60} \\ \\ m\text{ = }\frac{-60}{30}\text{ = -2} \end{gathered}[/tex]So the equation of the thread line would be;
[tex]N=\text{ -2m + 110}[/tex]