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Sagot :
We are given the following equation
[tex]5x-3y=15[/tex]There are multiple ways to graph this equation.
One method is by finding the x-intercept and y-intercept of the equation.
The other method is to find the slope and the y-intercept of the equation.
Let us find the x-intercept and y-intercept of the equation.
x-intercept:
This is the point where the line intersects the x-axis.
To find the x-intercept, substitute y = 0 into the equation.
[tex]\begin{gathered} 5x-3y=15 \\ 5x-3(0)_{}=15 \\ 5x=15 \\ x=\frac{15}{5} \\ x=3 \end{gathered}[/tex]So, the x-intercept is 3
y-intercept:
This is the point where the line intersects the y-axis.
To find the y-intercept, substitute x = 0 into the equation.
[tex]\begin{gathered} 5x-3y=15 \\ 5(0)-3y=15 \\ -3y=15 \\ y=\frac{15}{-3} \\ y=-5 \end{gathered}[/tex]So, the y-intercept is -5
Therefore, the correct graph is the one that intersects the x-axis at 3 and the y-axis at -5
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