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the given expression is
[tex]f(x)=3+\sqrt[]{x+3}[/tex]now put x = -1 for evaluate f(-1)
[tex]\begin{gathered} f(-1)=3+\sqrt[]{-1+3} \\ f(-1)=3+\sqrt[]{2} \end{gathered}[/tex]for f(2) put x = 2 in the equation
[tex]\begin{gathered} f(2)=3+\sqrt[]{2+3} \\ f(2)=3+\sqrt[]{5} \end{gathered}[/tex]the expression is
[tex]f(x)=3^x[/tex]put x = -1
[tex]f(-1)=3^{-1}=\frac{1}{3}[/tex]put x = 2
[tex]\begin{gathered} f(2)=3^2=3\times3=9 \\ f(2)=9 \end{gathered}[/tex]