First, we find the total area of the rectangle and then subtract the area of the two semicircles.
Area of rectangle:
[tex]A=width\times length[/tex]
Where:
width = 16 cm
length = 34 cm
Substitute the values:
[tex]A=16\times34=544[/tex]
We have that 2 semi-circles make a whole circle, and the area for the circle follows the formula:
[tex]A=\frac{\pi d^2}{4}[/tex]
Where:
d = diameter = 16 cm
pi = 3.14
Substitute the values:
[tex]A=\frac{(3.14)(16)^2}{4}=\frac{(3.14)(256)}{4}=(3.14)(64)=200.96[/tex]
Therefore, the area of the paper that remains is given by:
[tex]A=544-200.96=343.04[/tex]
Answer: 343.04 cm^2
