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An air traffic controller is tracking two planes. To start, Plane A was at an altitude of 890 meters, and Plane B was at an altitude of 1322 meters. Plane A islosing altitude at 16 meters per second, and Plane B is losing altitude at 25 meters per second.Let x be the number of seconds that have passed.(Questions included in Photo)

An Air Traffic Controller Is Tracking Two Planes To Start Plane A Was At An Altitude Of 890 Meters And Plane B Was At An Altitude Of 1322 Meters Plane A Islosin class=

Sagot :

Given:

• Altitude of plane A = 890 m

,

• Altitude of plane B = 1322 m

,

• Deceleration of plane A = 16 m/s

,

• Deceleration of plane B = 25 m/s

Let's solve for the following:

• (a) Let's write an expression for the altitude of the plane after x seconds.

We have:

Altitude of plane A = 890 - 16x

Altitude of plane B = 1322 - 25x

• (b). Let's write an equation to show when the two planes will have the same altitude.

To write this equation, let's equate both expressions.

We have:

890 - 16x = 1322 - 25x

ANSWER:

(a).

• Altitude of plane A = 890 - 16x

,

• Altitude of plane B = 1322 - 25x

(b).

• 890 - 16x = 1322 - 25x

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