Given:
• Altitude of plane A = 890 m
,• Altitude of plane B = 1322 m
,• Deceleration of plane A = 16 m/s
,• Deceleration of plane B = 25 m/s
Let's solve for the following:
• (a) Let's write an expression for the altitude of the plane after x seconds.
We have:
Altitude of plane A = 890 - 16x
Altitude of plane B = 1322 - 25x
• (b). Let's write an equation to show when the two planes will have the same altitude.
To write this equation, let's equate both expressions.
We have:
890 - 16x = 1322 - 25x
ANSWER:
(a).
• Altitude of plane A = 890 - 16x
,• Altitude of plane B = 1322 - 25x
(b).
• 890 - 16x = 1322 - 25x