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What happens to the period of a pendulum if the frequency is halved?

Sagot :

The period of a pendulum is related to its frequency by the following formula:

[tex]T=\frac{1}{f}[/tex]

If the frequency is halved we have:

[tex]T_2=\frac{1}{\frac{f}{2}}[/tex]

Simplifying we get:

[tex]T_2=2(\frac{1}{f})[/tex]

The term inside the parenthesis is the original period, therefore:

[tex]T_2=2T[/tex]

Therefore, if the frequency is halved the period is doubled.