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Sagot :
In order to find the amount of grams of CuSO4 needed to make 1 L of solution, we need to set up the percent solution formula:
%solution = (mass of solute/volume) * 100
We have:
%solution = 0.05%
volume = 1 L
Now adding these values into the formula:
0.05 = (mass/1)*100
0.05/100 = (mass/1)
0.0005 = mass/1
mass = 0.0005 grams of CuSO4 are needed
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