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Identify the Y-INTERCEPT of the graph from the following equation. Write your answer in coordinate pair form with parentheses * y = -3(x-4)2 + 1

Sagot :

Answer:

y-intercept would be on (0, -47)

Step by step explanation:

the y-intercept of a function is where the graph crosses the y-axis, then x=0.

To find the y-intercept of a quadratic function we have to substitute x=0 in the function:

[tex]y=-3(x-4)^2+1\text{ }[/tex][tex]\begin{gathered} y=-3(0-4)^2+1 \\ y=-3(-4)^2+1 \\ y=-3(16)+1 \\ y=-48+1 \\ y=-47 \end{gathered}[/tex]

Then, the y-intercept would be on (0, -47)

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