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6 Evaluate: 2 (V125a%b3 o 5a²6 0 25a-6 25a263 Оба?3

6 Evaluate 2 V125ab3 O 5a6 0 25a6 25a263 Оба3 class=

Sagot :

In order to solve this problem we must apply this simple rule:

√a.b.c = √a . √b . √c

So for that question we have:

³√125a6b³ = ³√125 . ³√a ⁶ . ³√b³

= 5 . a² . b

Let me explain now.

³√125 = 5 because we have 5 . 5 . 5 = 5³ = 125

³√a⁶ = a² because we can write a² . a² . a² = a⁶