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Sagot :
Given:
[tex]9x-7y=-3[/tex]The given equation of the line is written in standard form.
We will write the equation in slope-intercept form, we will solve the equation for (y) as follows:
[tex]\begin{gathered} 9x-7y=-3 \\ -7y=-9x-3\rightarrow(\div(-7)) \\ \frac{-7y}{-7}=\frac{-9x}{-7}+\frac{-3}{-7} \\ \\ y=\frac{9}{7}x+\frac{3}{7} \end{gathered}[/tex]So, the slope of the line = 9/7
We will answer the following questions:
a) What is the slope of a line parallel to this line?
The parallel lines have the same slope
So, the slope of a parallel line = 9/7
b) What is the slope of a line perpendicular to this line?
the product of the slopes of the perpendicular lines = -1
So, we will find the negative of the reciprocal of the given slope
So, the slope of the perpendicular line = -7/9
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