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Sagot :
Using conservation of momentum:
[tex]\begin{gathered} m1v1+m2v2=0 \\ _{\text{ }}Where\colon \\ m1=35\operatorname{kg} \\ m2=11\operatorname{kg} \\ v1=_{\text{ }}speed_{\text{ }}of_{\text{ }}the_{\text{ }}kid \\ v2=_{\text{ }}speed_{\text{ }}of_{\text{ }}the_{\text{ }}ball \\ so\colon \\ v1=-\frac{11}{35}v2 \\ _{\text{ }}where\colon \\ \frac{11}{35}<1 \\ so\colon \\ v2>v1 \end{gathered}[/tex]We can conclude that the answer is:
C. The kid will move to the left at a lower speed than the ball moves to the right.
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