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Sagot :
To answer this question we will use the following slope-point formula for the equation of a line:
[tex]y-y_1=m(x-x_1)\text{.}[/tex]Recall that two lines are parallel if they have the same slope.
Now, notice that the given equation is y=5x, therefore, the slope of the given equation is 5.
Using the slope-point formula, we get that the equation of the parallel line to y=5x that passes through (-5,5) is:
[tex]y-5=5(x-(-5))\text{.}[/tex]Simplifying the above equation we get:
[tex]\begin{gathered} y-5=5(x+5), \\ y-5=5x+25. \end{gathered}[/tex]Adding 5 to the above equation we get:
[tex]\begin{gathered} y-5+5=5x+25+5, \\ y=5x+30. \end{gathered}[/tex]Answer:
[tex]y=5x+30.[/tex]
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