Find accurate and reliable answers to your questions on IDNLearn.com. Ask anything and receive thorough, reliable answers from our community of experienced professionals.

Find the balance in the account after the given period.$3500 deposit earning 6.75% compounded monthly, after 6 monthsa. $3,619.80b. $3,743.70c. $3,748.22d. $4,860.36show your work thank you

Sagot :

The answer is $3,619.80.

To answer this question, we need to remember that the formula for compound interest is given by:

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

Where:

• A will be the final balance after the given period (accrued amount).

,

• P is the Principal (the amount we deposit). In this case, we have $3500.

,

• r is the interest rate. In this case, we have 6.75% = 6.75/100.

,

• n is the number of times per year compounded. In this case, the number of times is monthly, that is, n = 12.

,

• t is the time in years. Since we have here that we need the balance after 6 months, we have that 6 months is 1/2 year = 0.5year.

Then we can substitute the corresponding values into the general equation as follows:

[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ A=3500(1+\frac{\frac{6.75}{100}}{12})^{12(\frac{1}{2})} \\ A=3619.79864399 \end{gathered}[/tex]

If we round this result to two decimals, we have $3619.80

Using the given equation, we have:

[tex]f(x)=a(1+\frac{r}{n})^{xn}[/tex]

Where:

• a is the initial amount. In this case, a = $3500.

,

• r is the rate (of interest). In this case, r = 6.75% = 6.75/100.

,

• x is the time (in years). Since we have here 6 months, then 6 months is 1/2 year.

,

• n is the number of times per year compounded. In this case, the number of times is monthly, that is, n = 12.

Then we can apply the equation as follows:

x = 1/2

[tex]\begin{gathered} f(x)=a(1+\frac{r}{n})^{xn} \\ f(\frac{1}{2})=3500(1+\frac{\frac{6.75}{100}}{12})^{(\frac{1}{2})(12)} \\ f(\frac{1}{2})=3619.79864399 \end{gathered}[/tex]

If we round our result to the nearest hundredths, we have:

[tex]f(\frac{1}{2})=\$3,619.80[/tex]

We need to remember that:

[tex]6.75\%=\frac{6.75}{100}=0.0675[/tex]

And we have that n is the number of times per year compounded. In this case, the number of times is monthly, that is, n = 12. If we have a daily compounded amount, the value for n = 365. If it is quarterly compounded, we have that n = 4, and so on.

We got the same answer in both cases.

In summary, the balance in the account after the given period (6 months) is $3,619.80 (option a) - the interest period was 6 months (1/2 year).