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ANSWER
[tex]\begin{gathered} \text{ The specific heat of the metal block is 0.32 J/g}\degree C \\ \text{ The metal is Germanium} \end{gathered}[/tex]EXPLANATION
Given information
The thermal energy added is 3000 J
The mass of the metal block is 250.0 grams
The temperature change is 37.5 degrees Celcius
Firstly, we need to find the specific heat capacity of the metal block
To find the specific heat capacity of the metal block, follow the steps below
Step 1: Write the formula for calculating the heat of a substance
[tex]\begin{gathered} \text{ q = mc}\Delta\theta \\ \text{ Where} \\ q\text{ = heat energy} \\ m\text{ = mass} \\ c\text{ = specific heat capacity} \\ \Delta\theta=\text{ increase in temperature} \end{gathered}[/tex]Step 2: Substitute the given data into the formula in step 1 to find c
[tex]\begin{gathered} q\text{ = mc}\Delta\theta \\ \text{ make c the subject of the formula} \\ \text{ c = }\frac{q}{m\Delta\theta} \\ \text{ c = }\frac{3000}{250\text{ }\times37.5} \\ c\text{ = }\frac{3000}{9375} \\ c\text{ = 0.32 J/g}\degree C \end{gathered}[/tex]Hence, the specific heat capacity of the metal block is 0.32 J/g degrees Celcius
According to the table of specific heats, the metal that has the above specific heats is Germanium
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