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Using law of cosines:
[tex]a^2=b^2+c^2-2bc\cos (\alpha)[/tex]Where:
[tex]\begin{gathered} a=90 \\ b=450 \\ c=400 \\ \end{gathered}[/tex]So:
[tex]\begin{gathered} \cos (\alpha)=\frac{450^2+400^2-90^2}{2\cdot400\cdot450} \\ \cos (\alpha)=\frac{354400}{360000} \\ \alpha=\cos ^{-1}(\frac{59}{60}) \\ \alpha\approx10^{\circ} \end{gathered}[/tex]