Get detailed and reliable answers to your questions with IDNLearn.com. Get accurate answers to your questions from our community of experts who are always ready to provide timely and relevant solutions.

A tennis Court has an area of 312 yds. If the length is 2 yds more than twice the width, find the dimensions of the court.

Sagot :

Area = 312 yds

length (l) = 2width + 2

Formula

Area = length x width

Substitution

312 = (2 width + 2) (width)

312 = 2width^2 + 2width

2width^2 + 2width - 312 = 0

width^2 + width - 156 = 0

Factor

( x + 13)(x - 12) = 0

x1 = -13 x2 = 12

width = 12 yds

length = 2(12) + 2

length = 24 + 2

length = 26

Results

length = 26 yds

width = 12 yds