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. A tank contains 2500 L of argon gas. The pressure is13790 kPa and the temperature is 25ºC. How many moles of argon are in the tank?

Sagot :

Answer:

There are 13,917.2 moles of argon.

Explanation:

1st) The given information from the exercise is:

- Volume (V): 2500L

- Pressure (P): 13790kPa

- Temperature (T): 25°C

It is important to conver all the variables units to liters, atm and Kelvin:

- Conversion from kPa to atm:

[tex]13790kPa*\frac{0.00987atm}{1kPa}=136.11atm[/tex]

- Conversion from °C to K:

[tex]25+273.15=298.15K[/tex]

2nd) Now we can replace the values of pressure, volume and temperature in the Ideal Gases formula to calculate the number of moles:

[tex]\begin{gathered} P*V=n*R*T \\ 136.11atm*2500L=n*0.082\frac{atm*L}{mol*K}*298.15K \\ 340,275atm*L=n*24.45\frac{atm*L}{mol} \\ \frac{340,275atm*L}{24.45\frac{atm*L}{mol}}=n \\ 13,917.2mol=n \end{gathered}[/tex]

Finally, there are 13,917.2 moles of argon.

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