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ANSWER:
C) getting a sum less than 3
P(Ec) = 1/36
P(E )= 35/36
STEP-BY-STEP EXPLANATION:
When tossed two dice, the total number of elements is 36 and the statement tells us that E is the event of obtaining a sum of at least 3.
Therefore, the complementary event would be is getting a sum less than 3.
The elements that in the event E^c, that is, obtain a sum less than 3, is only one element (1,1).
Hence, the probabilities would be:
[tex]\begin{gathered} P(E^C)=\frac{1}{36} \\ P(E)=1-P(E^C)=1-\frac{1}{36}=\frac{35}{36} \end{gathered}[/tex]