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If a1 =1 and an = (an-1)2 + 5 then find the value of a3

Sagot :

We know that:

[tex]a_n=1[/tex]

and

[tex]a_n=(a_{n-1})^2+5[/tex]

To find the value of a3 we need to find the value of a2 first:

[tex]a_2=(a_{2-1})^2+5=(a_1)^2+5=(1)^2+5=1+5=6[/tex]

Then:

[tex]a_3=(a_{3-1})^2+5=(a_2)^2+5=(6)^2+5=36+5=41[/tex]

Therefore:

[tex]a_3=41[/tex]

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