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Find the equation (in terms of x ) of the line through thepoints (-2,9) and (1,0)y =

Find The Equation In Terms Of X Of The Line Through Thepoints 29 And 10y class=

Sagot :

To answer this question we will use the following formula for the equation of a line that passes through two given points:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1).[/tex]

Therefore the equation that passes through the points (1,0) and (-2,9) is:

[tex]y-0=\frac{9-0}{-2-1}(x-1).[/tex]

Simplifying the above result we get:

[tex]\begin{gathered} y=\frac{9}{-3}(x-1), \\ y=-3(x-1), \\ y=-3x+3. \end{gathered}[/tex]

Answer:

[tex]y=-3x+3.[/tex]

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