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Sagot :
Let the length of the rectangle = L
Width of the rectangle = w
The length of a rectangle is 12 ft longer than twice the width.
So,
[tex]l=12+2w[/tex]The perimeter of the rectangle is given by the formula:
[tex]P=2(l+w)[/tex]Given perimeter = 96 ft
Substitute with the perimeter and the equation of the length into the equation of the perimeter
So,
[tex]2(12+2w+w)=96[/tex]Solve the equation to find w:
[tex]\begin{gathered} 12+3w=\frac{96}{2} \\ 3w+12=48 \\ 3w=48-12 \\ 3w=36 \\ w=\frac{36}{3}=12 \end{gathered}[/tex]So, the length of the rectangle =
[tex]l=12+2w=12+24=36[/tex]So, the answer will be:
Length = 36 ft
Width = 12 ft
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