From the diagram, we get that the given triangles are similar because they have a pair of congruent angles.
The corresponding angles are:
[tex]\begin{gathered} \measuredangle F\cong\measuredangle J, \\ \measuredangle E\cong\measuredangle K, \\ \measuredangle D\cong\measuredangle L. \end{gathered}[/tex]
Therefore:
[tex]\Delta DEF\approx\Delta\text{LKJ.}[/tex]
Answer:
Similar, yes.
Theorem, Angle-Angle criteria.
Similarity statement DEF similar to LKJ.
