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14. The population of a town increased from 2,692 in 2008 to 5,712 in 2010. Find the absolute and percent increase. Give the percent increase to at least one decimal place.Absolute increase: peoplePercent increase: %

Sagot :

Hello

The population at 2008 = 2692

The population at 2010 = 5712

The absolute increase is simply the difference between the two population over the two time periods

Absolute increase is

[tex]5712-2692=3020[/tex]

The absolute difference is 3020

The percentage increase would be the ratio between the change in population to the original population multiplied by 100

[tex]\frac{5712-2692}{2692}\times100=\frac{3020}{2692}\times100=112.18\text{ \%}[/tex]

The percentage increase is approximately equals to 112.2%

From the calculation above, the absolute difference is 3020 and the percentage increase is 112.2%