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When 0.157 mol NH3 is reacted with excess HCl, 6.91 kJ of energy is released asheat. What is ΔH for this reaction per mole of NH3 consumed

Sagot :

NH3(aq)+HCl(aq)=NH4CI(aq) (ammonium chloride)

0.157 mol NH3 >> 6.91 kJ of energy

1 moles of NH3 >>>6.91 kJ/0.157

Delta H for this reaction per mole of NH3 consumed will therefore be :

ΔH =6.91 kJ/0.157

= 44.019kJ

∴ΔH per mole ≈44.02 kJ

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