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Sagot :
[tex]\begin{gathered} -2(x^3-7x^2+12x-10) \\ By\text{ trying the factors of -10, (x-5) is a factor of the polynomia} \end{gathered}[/tex][tex]\text{use long division method to get the other factors}[/tex][tex]\begin{gathered} \text{ Dividing }x^3-7x^2+12x-10^{}\text{ by (x-5)} \\ \text{ we have x}^2-2x+2 \\ \end{gathered}[/tex]
The expression then becomes
[tex]\begin{gathered} -2(x-5)(x^2-2x+2) \\ \\ (x^2-2x+2)\text{ cannot be factorized further} \\ \\ \text{The answer is -2(x-5)(x}^2-2x+2) \end{gathered}[/tex]
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