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You have the following equation given in the exercise:
[tex]\mleft(x-2\mright)\mleft(x+7\mright)=0[/tex]You can identify that the left side of the equation is factored. Then you can set up two equations using each expression inside the parentheses. Both equations must be equal to zero.
The first equation is:
[tex]x-2=0[/tex]Solve for "x" in order to find its value. To do this you need to add 2 to both sides of the equation:
[tex]\begin{gathered} x-2+(2)=0+(2) \\ x=2 \end{gathered}[/tex]The second equation is:
[tex]x+7=0[/tex]You can solve for "x" subtracting 7 from both sides of the equation:
[tex]\begin{gathered} x+7-(7)=0-(7) \\ x=-7 \end{gathered}[/tex]Therefore, the answer is:
[tex]x=2\text{ or }x=-7[/tex]