Get personalized and accurate responses to your questions with IDNLearn.com. Find the solutions you need quickly and accurately with help from our knowledgeable community.
Sagot :
ANSWER:
a) 1.91 cm/s
b) 0.039 cm/s
STEP-BY-STEP EXPLANATION:
a)
Here, since we need the velocity in cm/s, we assume that a small volume of blood passes through the section of the arteriole in a given time.
So, we have to divide the blood flow by the area of the arteriole section, therefore:
[tex]A=\pi\cdot\mleft(\frac{d}{2}\mright)^2[/tex]d = 0.08 mm = 0.008 cm
Replacing:
[tex]A=3.14\cdot\mleft(\frac{0.008}{2}\mright)^2=0.00005024=5.024\cdot10^{-5}cm^2[/tex]We calculate the speed by dividing the rate by the previous calculated area, like this:
[tex]\begin{gathered} v=\frac{q}{A} \\ \text{Replacing} \\ v=\frac{9.6\cdot10^{-5}}{5.024\cdot10^{-5}} \\ v=1.91\text{ cm/s} \end{gathered}[/tex]b)
First we find the area of the section of the capillaries:
[tex]\begin{gathered} d=6\cdot10^{-6}m=6\cdot10^{-4}cm \\ R\text{eplacing} \\ A=3.14\cdot\mleft(\frac{6\cdot10^{-4}}{2}\mright)^2 \\ A=0.0000002826=2.826\cdot10^{-7}cm^2 \end{gathered}[/tex]Now we have to remember that the flow is dividid in equal parts, so the volume by seconds is:
[tex]\begin{gathered} q=\frac{9.6\cdot10^{-5}}{8800} \\ q=1.09\cdot10^{-8}\frac{cm^3}{s} \end{gathered}[/tex]So the speed in this case is:
[tex]\begin{gathered} v=\frac{q}{A} \\ v=\frac{1.09\cdot10^{-8}}{2.826\cdot10^{-7}} \\ v=0.039\text{ cm/s} \end{gathered}[/tex]This latter speed is less than in the main arteriole.
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Find the answers you need at IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.
