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hello this is a trigonometry question hopefully you can help I did every thing else it's just the last one I can't get the reference angle for five in this question

Hello This Is A Trigonometry Question Hopefully You Can Help I Did Every Thing Else Its Just The Last One I Cant Get The Reference Angle For Five In This Questi class=

Sagot :

1) Let's set a proportion to find 5 radians equivalence to degrees and then locate which quadrant

[tex]\begin{gathered} \theta=5 \\ \pi-----180\circ \\ 5------x \\ \\ x=\frac{5\text{ x 180}}{\pi} \\ x=286.5\text{ or }\frac{900}{\pi} \\ \end{gathered}[/tex]

So since Quadrant IV is >270º and < 360º.

θ is in Quadrant IV

2) Let's find the Reference angle

Since the angle is in Quadrant IV, we subtract from 360º (or 2pi)

360º-286.5=73.5º

or

[tex]2\pi-\frac{900}{\pi}=\frac{2\pi-900}{\pi}[/tex]

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