We want to find the trigonometrical ratios of the angle B.
1.
[tex]\begin{gathered} \tan B=\frac{\text{opposite}}{\text{adjacent}} \\ =\frac{4}{3} \end{gathered}[/tex]
2.
[tex]\begin{gathered} \cos B=\frac{\text{adjacent}}{\text{hypotenuse}} \\ \cos B=\frac{3}{5} \end{gathered}[/tex]
3.
[tex]\begin{gathered} \sin B=\frac{\text{opposite}}{\text{hypotenuse}} \\ \sin B=\frac{4}{5} \end{gathered}[/tex]
Therefore, we find out that;
[tex]\tan B=\frac{4}{3},\cos B=\frac{3}{5},\sin B=\frac{4}{5}[/tex]
