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12) The rectangle is made up of 12 congruent (same size) squares. Find the perimeter of the rectangle if the area of the rectangle is equal to 432 cm^2.

Sagot :

The area of the rectangle is 432 cm².

The rectangle contains 12 squares with the same area. Then, the area of each square is:

432 cm²/12 = 36 cm²

The area of a square is A = l², then, the length of the side of each square is:

l = √A

l = √(36 cm²) = 6 cm

You can notice that the width of the rectangle is constituted by four squares, then, the with of the rectangle is:

w = 4l = 4(6 cm) = 24 cm

The height of the rectangle is constituted by three squares:

h = 3(6 cm) = 18 cm

Finally, the perimeter of a rectangle is given by the following formula:

P = 2w + 2h

by replacing the values of w and h you obtain:

P = 2(24 cm) + 2(18 cm)

P = 48cm + 36cm

P = 84 cm

Hence, the perimeter of the rectangle is 84 cm

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