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Sagot :
Given:
The intensity of Solar radiation is,
[tex]I=700\text{ W/m}^2[/tex]The area of the roof is,
[tex]A=7.48\text{ m}\times15.16\text{ m}[/tex]The time is,
[tex]\begin{gathered} t=1.09\text{ hours} \\ =1.09\times3600\text{ s} \end{gathered}[/tex]To find:
The incident solar energy
Explanation:
The incident energy is,
[tex]\begin{gathered} E=IAt \\ =700\times7.48\times15.16\times1.09\times3600 \\ =311.5\times10^6\text{ J} \end{gathered}[/tex]Hence, the incident energy is
[tex]311.5\times10^6\text{ J}[/tex]
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