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From the figure, the triangle ABC is right angled at C and:
[tex]AB=155,BC=93,AC=124[/tex]Use the trigonometric ratio of tan to get:
[tex]\tan A=\frac{BC}{AC}[/tex]Substitute the values to get:
[tex]\tan A=\frac{93}{124}=\frac{3}{4}[/tex][tex]\text{Hence tanA=}\frac{3}{4}[/tex]Option C is correct.