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A 125 cm3 soap bubble is formed outside, where the temperature is 10.0°C. It drifts through an open door, expands and pops in a house. If the maximum volume of the bubble could be 140 cm3, what is the temperature inside the house? (In C°)

Sagot :

In this question, we have a situation where a gas is in constant pressure but changing its volume and temperature, and the best way to solve a situation like this, is through the Charles's gas law formula, which shows the relationship between volume and temperature when the pressure is constant. The formula is:

V1/T1 = V2/T2

We have:

V1 = 125 cm3, or 0.125 Liters

T1 = 10.0°C, or 283 K

V2 = 140 cm3, or 0.140 Liters

T2 = ?

Now we add these values into the formula:

0.125/283 = 0.140/T2

0.000442 = 0.140/T2

T2 = 0.140/0.000442

T2 = 317 K, or 44°C

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