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Sagot :
[tex]\begin{gathered} E\colon\text{ Student take English} \\ A\colon\text{ Student take Art} \\ B\colon\text{ Student take both} \\ \\ \text{Total students:100} \\ \#E\colon40 \\ \#A\colon30 \\ \#B\colon12 \\ There\text{ are 18 students that doesn't take E and neither A} \\ \end{gathered}[/tex]
What is the probability that a student takes English or Art?:
[tex]P(E\text{ or A)}=\frac{\#E+\#A+B}{\text{Total}}=\frac{40+30+12}{100}=\frac{82}{100}=0.82[/tex]The probability that a student takes Ensglish or art is 82% (0.82)
What is the probability that a student takes English and Art?
[tex]P(E\text{ and A)}=\frac{\#B}{Total}=\frac{12}{100}=0.12[/tex]The probability that a student takes English and Art is 12% (0.12)
What is the probability that a student does not take English?
[tex]\begin{gathered} P(\text{not E)}=1-P(E) \\ \\ P(E)=\frac{\#E+\#B}{\text{Total}}=\frac{40+12}{100}=\frac{52}{100}=0.52 \\ \\ P(\text{not E)}=1-0.52=0.48 \end{gathered}[/tex]The probability that a student does not take English is 48% (0.48)
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