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Given the function -x^2 + x + 6 what is the horizontal distance between zeros?

Given The Function X2 X 6 What Is The Horizontal Distance Between Zeros class=

Sagot :

Answer:

The horizontal distance is 5

Explanation:

The zeros of a function f(x) are the values of x which:

[tex]f(x)=0[/tex]

In this case, we have the function:

[tex]-x^2+x+6[/tex]

We want to find the zeros:

[tex]-x^2+x+6=0[/tex]

Now, we can use the quadratic formula:

[tex]x_{1,2}=\frac{-1\pm\sqrt{1^2-4(-1)6}}{2(-1)}[/tex][tex]x_{1,2}=\frac{-1\pm\sqrt{1+4\cdot6}}{-2}[/tex][tex]x_{1,2}=\frac{1\pm\sqrt{1+24}}{2}[/tex][tex]x_{1,2}=\frac{1\pm\sqrt{25}}{2}[/tex][tex]x_{1,2}=\frac{1\pm5}{2}[/tex]

Then:

[tex]\begin{gathered} x_1=\frac{1+5}{2}=\frac{6}{2}=3 \\ \end{gathered}[/tex][tex]x_2=\frac{1-5}{2}=\frac{-4}{2}=-2[/tex]

The two roots are x = -2 and x = 3

To find the distance, we take the absolute value of the difference:

[tex]Distance=|-2-3|=|-5|=5[/tex]

The distance is 5