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Sagot :
SOLUTION
The equation of a line in slope intercept form is given as
[tex]\begin{gathered} y=mx+b \\ where\text{ m is slope and b is intercept on the y-axis } \end{gathered}[/tex]Comparing this to
[tex]\begin{gathered} y=-\frac{1}{8}x+3 \\ the\text{ the slope m = -}\frac{1}{8} \\ and\text{ the intercept b = 3} \end{gathered}[/tex]For two lines to be perpendicular, their product of their slope should be = -1
So we have
[tex]\begin{gathered} m_1m_2=-1 \\ -\frac{1}{8}\times m_2=-1 \\ m_2=\frac{-1}{-\frac{1}{8}} \\ =-1\times-\frac{8}{1} \\ =\frac{8}{1} \\ =8 \end{gathered}[/tex]So the equation of the line becomes
[tex]y=8x+3[/tex]So the best choice should be one with slope of 8
If you bring 8x to meet y, we have
[tex]y-8x=3[/tex]So the correct answer is the equation looking like this above
So the best answer is
y - 8x = -2, the last option is the answer
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