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Sagot :
A). According to given diagram:
i) The base of the traingle is = 8 units
And the height of the triangle is = 3 units
So the area of the triangle is:
[tex]\begin{gathered} A=\frac{1}{2}\times3\times8 \\ A=12\text{ sq. units} \end{gathered}[/tex]ii) If we use scale factor of size 2 then:
The base of the traingle is = 16 units
And the height of the triangle is = 6 units
iii) So the area of the triangle is:
[tex]\begin{gathered} A^{\prime}=\frac{1}{2}\times6\times16 \\ A^{\prime}=48\text{ sq units} \end{gathered}[/tex]And the ratio of areas is:
[tex]\begin{gathered} \frac{A^{\prime}}{A}=\frac{48}{12} \\ \frac{A^{\prime}}{A}=4\colon1 \end{gathered}[/tex]
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