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we have
x^2+6x=-22
complete the square
Divide 6 by 2
6/2=3
squared
3^2=9
adds and subtract 9 to the equation
(x^2+6x+9-9)=-22
(x^2+6x+9)=-22+9
rewrite as perfect squares
(x+3)^2=-13
Remember that
i^2=-1
square root both sides
[tex]\begin{gathered} x+3=\pm\sqrt[]{-13} \\ x+3=\pm i\sqrt[]{13} \\ x=-3\pm i\sqrt[]{13} \end{gathered}[/tex]